Z^2+(1+2i)z=0

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Solution for Z^2+(1+2i)z=0 equation:


Simplifying
Z2 + (1 + 2i) * z = 0

Reorder the terms for easier multiplication:
Z2 + z(1 + 2i) = 0
Z2 + (1 * z + 2i * z) = 0

Reorder the terms:
Z2 + (2iz + 1z) = 0
Z2 + (2iz + 1z) = 0

Solving
Z2 + 2iz + 1z = 0

Solving for variable 'Z'.

Move all terms containing Z to the left, all other terms to the right.

Add '-2iz' to each side of the equation.
Z2 + 2iz + -2iz + 1z = 0 + -2iz

Combine like terms: 2iz + -2iz = 0
Z2 + 0 + 1z = 0 + -2iz
Z2 + 1z = 0 + -2iz
Remove the zero:
Z2 + 1z = -2iz

Add '-1z' to each side of the equation.
Z2 + 1z + -1z = -2iz + -1z

Combine like terms: 1z + -1z = 0
Z2 + 0 = -2iz + -1z
Z2 = -2iz + -1z

Simplifying
Z2 = -2iz + -1z

Reorder the terms:
Z2 + 2iz + z = -2iz + 2iz + -1z + z

Combine like terms: -2iz + 2iz = 0
Z2 + 2iz + z = 0 + -1z + z
Z2 + 2iz + z = -1z + z

Combine like terms: -1z + z = 0
Z2 + 2iz + z = 0

The solution to this equation could not be determined.

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